(PHP 4, PHP 5, PHP 7, PHP 8)
escapeshellcmd — shell 元字符转义
$command
) : stringescapeshellcmd() 对字符串中可能会欺骗 shell 命令执行任意命令的字符进行转义。 此函数保证用户输入的数据在传送到 exec() 或 system() 函数，或者 执行操作符 之前进行转义。
反斜线（\）会在以下字符之前插入：
&#;`|*?~<>^()[]{}$\, \x0A
和 \xFF。 ' 和 "
仅在不配对儿的时候被转义。
在 Windows 平台上，所有这些字符以及 % 和 ! 字符都会被空格代替。
command要转义的命令。
转义后的字符串。
Example #1 escapeshellcmd() example
<?php
// 我们故意允许任意数量的参数
$command = './configure '.$_POST['configure_options'];
$escaped_command = escapeshellcmd($command);
system($escaped_command);
?>
escapeshellcmd() 应被用在完整的命令字符串上。 即使如此，攻击者还是可以传入任意数量的参数。 请使用 escapeshellarg() 函数 对单个参数进行转义。
| 版本 | 说明 |
|---|---|
| 5.4.43, 5.5.27, 5.6.11 | 感叹号会被空格所替换。 |
escaping strings for a shell is tricky.
If your target system is windows give up now. windows isn't even self consisitent in how to escape stuff.
if unix convert everything to octal - although this is hardest to implement it's the easiest to implement correctly - there are no special cases..
.
There is a quirk to be aware of regarding use of echo. If you have a command which you want to execute which takes input from STDIN, you would normally do:
<?php $output = shell_exec("echo $input | /the/command"); ?>
Unfortunately, this is a *bad idea* and will make your script unportable, providing a very hard-to-trace bug on some systems. Depending on how the server is set up, /bin/sh will either call /bin/bash or /bin/dash, and these have very different versions of echo. Never use echo; use printf instead which is consistent. How do you escape for printf? Do this:
<?php
$input = 'string to be passed *exactly* to the command';
//Escape only what is needed to get by PHP's parser; we want
//the string data PHP is holding in its buffer to be passed
//exactly to stdin buffer of the command.
$cmd = str_replace(array('\\', '%'), array('\\\\', '%%'), $input);
$cmd = escapeshellarg($cmd);
$output = shell_exec("printf $cmd | /path/to/command");
?>
For the paranoid, this torture test verifies that both shell escaping and printf's own escaping are handled correctly. Use with confidence!
<?php
$test = 'stuff bash interprets, space: # & ; ` | * ? ~ < > ^ ( ) [ ] { } $ \ \x0A \xFF. \' " %'.PHP_EOL.
'stuff bash interprets, no space: #&;`|*?~<>^()[]{}$\\x0A\xFF.\'\"%'.PHP_EOL.
'stuff bash interprets, with leading backslash: \# \& \; \` \| \* \? \~ \< \> \^ \( \) \[ \] \{ \} \$ \\\ \\\x0A \\\xFF. \\\' \" \%'.PHP_EOL.
'printf codes: % \ (used to form %.0#-*+d, or \\ \a \b \f \n \r \t \v \" \? \062 \0062 \x032 \u0032 and \U00000032)';
echo "These are the strings we are testing with:".PHP_EOL.$test.PHP_EOL;
$cmd = $test;
$cmd = str_replace(array('\\', '%'), array('\\\\', '%%'), $test);
$cmd = escapeshellarg($cmd);
echo PHP_EOL."This is the output using the escaping mechanism given:".PHP_EOL;
echo `printf $cmd | cat`.PHP_EOL;
echo PHP_EOL."They should match exactly".PHP_EOL;
?>
Mind it does not escape ! (exclamation mark). So if you want to i.e. printf() commands for later use in shell (i.e. by pasting to the console) you need to escape all exclamation marks or shell will try to process ! as history reference. This approach shall suffice:
<?php $scaped = str_replace('!', '\!', escapeshellarg( $str ) ); ?>
This function is great -- except when you need to legitimately use an escaped character as part of your command. The code below leaves the parts of the command that are enclosed within single quotes alone, but escapes the rest eg:
"echo Never use the '<blink>' tag ; cat /etc/passwd"
becomes:
"echo Never use the '<blink>' tag \; cat /etc/passwd"
and not:
"echo Never use the '\<blink\>' tag \; cat /etc/passwd"
i.e, we really want the ';' escaped, but not the HTML tag. I really needed the code below in order to run the external ImageMagick's 'convert' command properly and safely...
<?php
// Escape whole string
$cmdQ = escapeshellcmd($cmd);
// Build array of quoted parts, and the same escaped
preg_match_all('/\'[^\']+\'/', $cmd, $matches);
$matches = current($matches);
$quoted = array();
foreach( $matches as $match )
$quoted[escapeshellcmd($match)] = $match;
// Replace sections that were single quoted with original content
foreach( $quoted as $search => $replace )
$cmdQ = str_replace( $search, $replace, $cmdQ );
return $cmdQ;
?>
I've got a php script that needs to pass a username and password via exec to a perl script. The problem is valid password characters were getting escaped...
Here's a little perl function I wrote to fix it.
sub unescape_string {
my $string = shift;
# all these interpolated regex's are slow, so if there's no
# backslash in the string don't bother with it
# index() is faster then a regex
if ( ! index($string,'\\\\') ) {
return $string;
}
my @characters = ('#', '&', ';', '`', '|', '*', '?', '~', '<', '>', '^', '(', ')',
'[', ']', '{', '}', '$', '\\', ',', ' ', '\x0A', '\xFF' );
my $character;
foreach $character (@characters) {
$character = quotemeta($character);
my $pattern = "\\\\(" . $character . ")";
$string =~ s/$pattern/$1/g;
}
return $string;
}
Hope this is useful.
Well guys, i find it very hard that escapeshellarg and escapeshellcmd are forcely run when passing a command to exec, system or popen, when safe_mode is turned on.
Right now, i did not find any working solution to pass commands like this:
cmd -arg1 -arg2 "<BLA varname=\"varvalue\" varname1=\"varvalue1\" />"
it is just the case, that the parameter for arg2 which is a string that looks like an HTML-Tag with various attributes set, all attributes of the string in arg2 gets splitted by the whitespaces within. this wont happen with safe_mode turned off, so it must be one of the escapefunctions, that breaks functionality.
In order to circumvent this, i have made a temporary solution, which dynamically creates a skriptfile (by fopen), which just contains the whole command with arguments, and then execute that skriptfile. i dont like that solution, but in the other hand, safe_mode cannot be easily turned off on that server.
the main reason for quoting a command is that it not multiple command can be joined. i don't know for sure if this is the right syntax but remeber that this can do some nice security breaks. here's one way of how to know exactly what your trying to break into for.
normal any user on linux can view almost any directory so:
ls / -als will print a complete list of any file in the linux filesystem including its size, security and hidden files as well.
now the output would only become known to php and never will the user be able to view this data unless the php script would actual start to print it out. like passtru does!! but a good php coder knows never to use passtru unless not otherwise possible.
but what would happen if you can direct the output from ls also from that same commandline to a file in the webroot most webserver still default their base-webroot to /var/www/ so storing it there in text file to download it later and you can simply take coffee while checking wich files can be read by php security mode and then simply use the cp command to copy those to the webroot and download them to your own hard-disk. without a list of the files you can only guess where to copy from! and thats harder then guessing the root password.
so if the first command was quoted it is not possible to attach another command because of a syntax error. think of all the thinks you can do once you got a complete list of every file on the filesystem. including mounted once via NFS and others. security starts at keeping the door hidden.
also another nice command for hanging the webserver can be "php <?php while(true){ exec('ls / -als'); }; ?>" this keeps creating a file list on the entire filesystem wich not only keeps the hard-disk(s) bussy but also memory and cpu wich must store the returned list. so keeping in mind not all command accepted from users can be used blind.
actualy never accept any command from external sources only proven built-in predefined commands should be executed.
This function does not work as shown in the php.net examples.
If you put your encoded filename into double-quotes as they suggest, then it will break on certain characters in filenames, such as ampersand.
For example if you have a filename called "foo & bar.jpg" and you use this function on it, your resulting filename when double-quoted will produce this and not be found:
"foo \& bar.jpg"
If you need to have a single argument where spaces are included then do not use this function with added double-quotes, use escapeshellarg() which encloses the whole string in single quotes.
I do not understand which purpose this particular function is intended for. I can't see any use for it, unless you pass it through another function and convert spaces " " to "\ ", which would allow you to use the string directly on the command line.