gmp_gcd

(PHP 4 >= 4.0.4, PHP 5, PHP 7, PHP 8)

gmp_gcdCalculate GCD

说明

gmp_gcd ( GMP|int|string $num1 , GMP|int|string $num2 ) : GMP

Calculate greatest common divisor of num1 and num2. The result is always positive even if either of, or both, input operands are negative.

参数

num1

GMP 对象或 int ,或数字string

num2

GMP 对象或 int ,或数字string

返回值

A positive GMP number that divides into both num1 and num2.

范例

Example #1 gmp_gcd() example

<?php
$gcd 
gmp_gcd("12""21");
echo 
gmp_strval($gcd) . "\n";
?>

以上例程会输出:

3

参见

User Contributed Notes

me at abiusx dot com 10-Apr-2020 01:48
function gcd($a,$b)
{
    return $b ? gcd($b, $a%$b) : $a;
}

This is pretty fast and short, also easy to remember. If $b is zero, return a, otherwise swap and mod.
delboy1978uk at gmail dot com 24-Oct-2017 05:05
I wanted this functionality without having to install the extension.

So here's a script I wrote to find out the greatest common denominator:

<?php

// Our fraction, 3/12, could be written better
$numerator = 3;
$denominator = 12;

/**
 * @param int $num
 * @return array The common factors of $num
 */
function getFactors($num)
{
   
$factors = [];
   
// get factors of the numerator
   
for ($x = 1; $x <= $num; $x ++) {
        if (
$num % $x == 0) {
           
$factors[] = $x;
        }
    }
    return
$factors;
}

/**
 * @param int $x
 * @param int $y
 */
function getGreatestCommonDenominator($x, $y)
{
   
// first get the common denominators of both numerator and denominator
   
$factorsX = getFactors($x);
   
$factorsY = getFactors($y);
   
   
// common denominators will be in both arrays, so get the intersect
   
$commonDenominators = array_intersect($factorsX, $factorsY);
   
   
// greatest common denominator is the highest number (last in the array)
   
$gcd = array_pop($commonDenominators);
    return
$gcd;
}

// divide the numerator and denomiator by the gcd to get our refactored fraction
$gcd = getGreatestCommonDenominator($numerator, $denominator);
echo (
$numerator / $gcd) .'/'. ($denominator / $gcd); // we can use divide (/) because we know result is an int :-)

Which you can see running here https://3v4l.org/uTucY
sean__remove__ at eternalrise_r_emove__ dot com 10-Nov-2008 07:50
Here's my solution for getting the GCD of several numbers.

<?php

/*
 * function gcd()
 *
 * returns greatest common divisor
 * between two numbers
 * tested against gmp_gcd()
 */
function gcd($a, $b)
{
    if (
$a == 0 || $b == 0)
        return
abs( max(abs($a), abs($b)) );
       
   
$r = $a % $b;
    return (
$r != 0) ?
       
gcd($b, $r) :
       
abs($b);
}

/*
 * function gcd_array()
 *
 * gets greatest common divisor among
 * an array of numbers
 */
function gcd_array($array, $a = 0)
{
   
$b = array_pop($array);
    return (
$b === null) ?
        (int)
$a :
       
gcd_array($array, gcd($a, $b));
}

?>
limas at kultur-online dot at 01-Dec-2007 10:44
The previous function returns just 1 under php 5.2.4  but the following seems to work (m>0,n>0):

function gcd($m,$n)
{
    $_m=$m;$r=1;
    if($m<$n){$t=$m;$m=$n;$n=$t;}   
    while($r)
    {
        $r=(floor($m/$n)*$n)-$m;     
        $_n=$n;$n=$r;$m=$_m;
    }    
    return abs($_n);
}
bigkm1 at gmail dot com 25-Aug-2006 09:33
here is an elegant recursive solution
<?php   

function gcd($a,$b) {
    return (
$a % $b) ? gcd($b,$a % $b) : $b;
}

?>
scr02001 at student dot mdh dot se 16-Aug-2003 06:58
If you do not consier a or b as possible negative numbers, a GCD funktion may return a negative GCD, wich is NOT a greatest common divisor, therefore a funktion like this may be better. This considers the simplyfying of (-3)-(-6) where gcd on -3 and -6 would result in 3, not -3 as with the other function. (-3)-(-6) is (-1)-(-2) NOT (1)-(2)

function eGCD($a,$b){
  if($a < 0)         $a=0-$a;
  if($b < 0 )        $b=0-$b;
  if($a == 0 || $b == 0)    return 1;
  if($a == $b)              return a;
 
do{
  $rest=(int) $a % $b;  $a=$b; $b=$rest;
  }while($rest >0);
return $a;
}
Ludwig Heymbeeck 12-Jan-2003 10:33
The following function is more accurate:

function GCD($num1, $num2) {
/* finds the greatest common factor between two numbers */
   while ($num2 != 0){
     $t = $num1 % $num2;
     $num1 = $num2;
     $num2 = $t;
   }
   return $num1;
}
x-empt-php dot net at ispep dot cx 06-Jul-2002 11:16
No need to compile gmp functions in just for the GCD function...  use this one instead:

function GCD($num1, $num2) {
 /* finds the greatest common factor between two numbers */
    if ($num1 < $num2) {
        $t = $num1;
        $num1 = $num2;
        $num2 = $t;
    }
    while ($t = ($num1 % $num2) != 0) {
        $num1 = $num2;
        $num2 = $t;
    }
    return $num2;
}
PHP8中文手册 站长在线 整理 版权归PHP文档组所有