imagecolorclosest

(PHP 4, PHP 5, PHP 7, PHP 8)

imagecolorclosest — 取得与指定的颜色最接近的颜色的索引值

说明

imagecolorclosest ( resource $image , int $red , int $green , int $blue ) : int

返回图像调色板中与指定的 RGB 值最"接近"的颜色。

指定的颜色与调色板中的每个颜色的"距离"的计算方法是把 RGB 值当成三维空间中点的坐标。

如果从文件创建了图像，只有图像中使用了的颜色会被辨析。仅出现在调色板中的颜色不会被辨析。

参见 imagecolorexact()。

User Contributed Notes

Hayley Watson 23-Jul-2017 04:33
RGB space isn't the best choice for measuring the distance between two colours, since it ignores, for example, the fact that we count both dark green and light green as "green" (the RGB distance between #000000 and #7f7f7f is the same as the distance between #000000 and #5443c0 - a slightly darkened SlateBlue).

A better choice of colour space that conforms better to how colours are perceived is the so-called Lab space, which measures colours according to how light/dark, red/green, and yellow/blue they are. (There are still better models, but they come at the expense of increased computation.)

<?php

function warp1($c)
{
    if($c > 10.3148)
    {
        return pow((561 + 40*$c)/10761, 2.4);
    }
    else
    {
        return $c / 3294.6;
    }
}
function warp2($c)
{
    if($c > 0.008856)
    {
        return pow($c, 1/3);
    }
    else
    {
        return 7.787 * $c + 4/29;
    }
}
function rgb2lab($rgb)
{
    [$red, $green, $blue] = array_map('warp1', $rgb);

    $x = warp2($red * 0.4339 + $green * 0.3762 + $blue * 0.1899);
    $y = warp2($red * 0.2126 + $green * 0.7152 + $blue * 0.0722);
    $z = warp2($red * 0.0178 + $green * 0.1098 + $blue * 0.8730);

    $l = 116*$y - 16;
    $a = 500 * ($x - $y);
    $b = 200 * ($y - $z);
   
    return array_map('intval', [$l, $a, $b]);
}

function generate_palette_from_image($image)
{
    $pal = [];
    $width = imagesx($image);
    $height = imagesy($image);
    for($x = 0; $x < $width; ++$x)
    {
        for($y = 0; $y < $height; ++$y)
        {
            $pal[] = imagecolorat($image, $x, $y);
        }
    }
    return array_map(function($col)use($image)
    {
        $rgba = imagecolorsforindex($image, $col);
        return [$rgba['red'], $rgba['green'], $rgba['blue']];
    },    array_unique($pal));
}

function closest_rgb_in_palette($rgb, $palette)
{
    // Quick return when the exact
    // colour is in the palette.
    if(($idx = array_search($rgb, $palette)) !== false)
    {
        return $idx;
    }
    [$tl, $ta, $tb] = rgb2lab($rgb);
    $dists = array_map(function($plab)use($tl, $ta, $tb)
    {
        [$pl, $pa, $pb] = $plab;
        $dl = $pl - $tl;
        $da = $pa - $ta;
        $db = $pa - $tb;
        return $dl * $dl + $da * $da + $db * $db;
    }, array_map('rgb2lab', $palette));
    return array_search(min($dists), $dists);
}

function closest_rgb_in_image($rgb, $image)
{
    $palette = generate_palette_from_image($image);
    return $palette[closest_rgb_in_palette($rgb, $palette)];
}

$lena = imagecreatefrompng('lena.png');
$red = closest_rgb_in_image([255,0,0],$lena);
echo join(' ', $red);  // 228 71 82

?>

If you're going to be matching a lot of colours to a palette, you may want to precompute and reuse the Lab palette, instead of generating it fresh each time as done here.
info at codeworx dot ch 09-Nov-2011 02:21
Here is a function that compares two HEX colors for similarity. This can be useful if you want to detect colors that are not different enough to see for the naked eye. It returns a bool: TRUE if the colors are similar to each other (within tolerance) or FALSE if they are different enough.
I tested a few colors and came up with a tolerance of 35 (rgb value - should be between 0 and 255) but you can change that tolerance by passing a third parameter to the function.

<?php
function compareColors ($col1, $col2, $tolerance=35) {
    $col1Rgb = array(
        "r" => hexdec(substr($col1, 0, 2)),
        "g" => hexdec(substr($col1, 2, 2)),
        "b" => hexdec(substr($col1, 4, 2))
    );
    $col2Rgb = array(
        "r" => hexdec(substr($col2, 0, 2)),
        "g" => hexdec(substr($col2, 2, 2)),
        "b" => hexdec(substr($col2, 4, 2))
    );
    return ($col1Rgb['r'] >= $col2Rgb['r'] - $tolerance && $col1Rgb['r'] <= $col2Rgb['r'] + $tolerance) && ($col1Rgb['g'] >= $col2Rgb['g'] - $tolerance && $col1Rgb['g'] <= $col2Rgb['g'] + $tolerance) && ($col1Rgb['b'] >= $col2Rgb['b'] - $tolerance && $col1Rgb['b'] <= $col2Rgb['b'] + $tolerance);
}
?>
MagicalTux at FF dot st 28-Jun-2005 06:22
A way to get each time an answer :

<?php
function imagegetcolor($im, $r, $g, $b) {
        $c=imagecolorexact($im, $r, $g, $b);
        if ($c!=-1) return $c;
        $c=imagecolorallocate($im, $r, $g, $b);
        if ($c!=-1) return $c;
        return imagecolorclosest($im, $r, $g, $b);
}
?>

If the *exact* color is found in the image, it will be returned. If we don't have the exact color, we try to allocate it. If we can't allocate it, we return the closest color in the image.
Vikrant Korde <vakorde at hotmail dot com> 11-Oct-2003 08:10
This functuion is useful when you are dealing with previously present images like .png, .jpg, etc. You can use this function for writing a text on the image.

For me the function imagecolorallocate() was returning the -1 value. after lot of RnD and site search i found a function use of imagecolorclosest(). This solved my problem of writing the text on the image with customised color.

Actually previously it was writing on the image but the color was not distinct. It was using the same color as of that background image.

The following code segment was fine with me.

header ("Content-type: image/jpeg");
$im = imagecreatefromjpeg("BlankButton.jpg");
$white = imageColorClosest($im, 255,255,255);
// this is for TTF fonts
imagettftext ($im, 20, 0, 16, 30, $white, "/usr/X11R6/lib/X11/fonts/TTF/luximb.ttf", "Vikrant");

//this is for notmal font
imagestring($im, 4, 0,0,"Korde", $white);
imagejpeg($im,"",150);
imagedestroy ($im);
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