mysql_data_seek

(PHP 4, PHP 5)

mysql_data_seek — 移动内部结果的指针

说明

mysql_data_seek ( resource $result , int $row_number ) : bool

mysql_data_seek() 将指定的结果标识所关联的 MySQL 结果内部的行指针移动到指定的行号。接着调用 mysql_fetch_row() 将返回那一行。

row_number 从 0 开始。row_number 的取值范围应该从 0 到 mysql_num_rows - 1。但是如果结果集为空（mysql_num_rows() == 0），要将指针移动到 0 会失败并发出 E_WARNING 级的错误，mysql_data_seek() 将返回 false。

参数

result

resource 型的结果集。此结果集来自对 mysql_query() 的调用。

row_number

想要设定的新的结果集指针的行数。

返回值

成功时返回 true， 或者在失败时返回 false。

范例

Example #1 mysql_data_seek() 例子

<?php
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
    die('Could not connect: ' . mysql_error());
}
$db_selected = mysql_select_db('sample_db');
if (!$db_selected) {
    die('Could not select database: ' . mysql_error());
}
$query = 'SELECT last_name, first_name FROM friends';
$result = mysql_query($query);
if (!$result) {
    die('Query failed: ' . mysql_error());
}
/* fetch rows in reverse order */
for ($i = mysql_num_rows($result) - 1; $i >= 0; $i--) {
    if (!mysql_data_seek($result, $i)) {
        echo "Cannot seek to row $i: " . mysql_error() . "\n";
        continue;
    }

    if (!($row = mysql_fetch_assoc($result))) {
        continue;
    }

    echo $row['last_name'] . ' ' . $row['first_name'] . "<br />\n";
}

mysql_free_result($result);
?>

注释

Note:

本扩展自 PHP 5.5.0 起已废弃，并在自 PHP 7.0.0 开始被移除。应使用 MySQLi 或 PDO_MySQL 扩展来替换之。参见 MySQL：选择 API 指南来获取更多信息。 用以替代本函数的有：

Note:

mysql_data_seek() 只能和 mysql_query() 结合起来使用，而不能用于 mysql_unbuffered_query()。

参见

User Contributed Notes

saeed at photobookworldwide dot com 25-Nov-2011 06:30
Here, you can find the current pointer of selected row easily:

<?php
//selected row with id=4
$id    =    "4";

$result    =    mysql_query("select * from jos_components");

$num    =    mysql_num_rows($result);

for($i=0;$i<$num;$i++){
   
    mysql_data_seek($result,$i);
 
    $row    =    mysql_fetch_assoc($result);
   
    if($row['id']    ==    $id){
       
        $pointer    =    $i;
    }

 
}

// current pointer for selected row
echo $pointer;
?>
Daniel 28-Aug-2008 02:59
Here is a simple function to "peek" at the position of the internal pointer in a query result:

<?php
function mysql_pointer_position($result_set) {
        $num_rows = mysql_num_rows($result_set);
        $i = 0;
        while($result = mysql_fetch_array($result_set)) {
            $i++;
        }
        $pointer_position = $num_rows - $i;

//Return pointer to original position
        if($pointer_position <= $num_rows - 1) {
            mysql_data_seek($result_set, $pointer_position);
        }
        return $pointer_position;
    }
?>
30-May-2006 01:52
A helpful note about the 'resource' data type.

Since the 'resource' variable is pointing to a row in a result set at any given time, you can think of it as being passed to this function by reference every time you pass it or assign it to a variable.

<?

$sql = "SELECT * from <table>";
$result = mysql_query($sql);
$temp_result = $result;

while ($row = mysql_fetch_assoc($temp_result)) {
    // do stuff with $row
}

while ($row = mysql_fetch_assoc($result)) {
    // This code will never run because the 'resource' variable is pointing past the end of the result set,
    // even though it was *not* assigned by reference to $result2.
}

?>

Therefore, the following snipits are functionally identical:

<?

// Start snipit 1

$sql = "SELECT * from <table>";
$result = mysql_query($sql);

while ($row = mysql_fetch_assoc($result)) {
    // do stuff with $row
}

mysql_data_seek($result, 0);

while ($row = mysql_fetch_assoc($result)) {
    // do other stuff with $row
}

// Start snipit 2

$sql = "SELECT * from <table>";
$result = mysql_query($sql);
$temp_result = $result;

while ($row = mysql_fetch_assoc($temp_result)) {
    // do stuff with $row
}

mysql_data_seek($result, 0);

while ($row = mysql_fetch_assoc($temp_result)) {
    // do other stuff with $row
}

?>
arturo_b at hotmail dot com 20-Apr-2005 08:53
hello, this script would be easy to understand for those that are novice in php whose want to understand about this function:

the table "user" have 2 columns "id" and "name".
"user" content:
position 0: "id"=195342481 "name"='Arthur'
position 1: "id"=179154675 "name"='John'
>>position 2<<: "id"=157761949 "name"='April' >>third row<<
position 3: "id"=124492684 "name"='Tammy'
position 4: "id"=191346457 "name"='Mike'

<?php
  mysql_connect("localhost", "root")
  mysql_select_db("test");
  $sql = mysql_query("select * from user");
  mysql_data_seek($sql, 2);
  echo "<table border=1>";
  while ($row = mysql_fetch_row($sql)){
    echo "<tr><td>$row[0]</td><td>$row[1]</td></tr>";
  }
  echo "</tabla>";
?>

explanation:
mysql_data_seek move internal result pointer to the third row of table user. Thus mysql_fetch_row will begin by april?s row.
b.steinbrink at g m x dot de 08-Dec-2004 11:09
to kennethnash1134 at yahoo dot com

your loop can be done like this as well and i guess this is faster:

$r=mysql_query("select user,id,ip from accounts limit 10");

unset($users); // Just to be sure
while($users[] = mysql_fetch_row);
array_pop($users); // Drop the last entry which is FALSE
kennethnash1134 at yahoo dot com 26-Mar-2004 12:12
/*here is a nice function for converting a mysql result row set into a 2d array, a time saver if need small data from several rows, saves you from having to do Alot of queries... would be nice to have this built into PHP future versions :) */

// simple example query
$r=mysql_query("select user,id,ip from accounts limit 10");

//starts the for loop, using mysql_num_rows() to count total
//amount of rows returned by $r
for($i=0; $i<mysql_num_rows($r); $i++){
             //advances the row in the mysql resource $r
    mysql_data_seek($r,$i);
             //assigns the array keys, $users[row][field]
    $users[$i]=mysql_fetch_row($r);
}

//simple, hope someone can use it :)
// -Kenneth Nash
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