mysqli_result::fetch_object

mysqli_fetch_object

(PHP 5, PHP 7, PHP 8)

mysqli_result::fetch_object -- mysqli_fetch_objectReturns the current row of a result set as an object

说明

面向对象风格

public mysqli_result::fetch_object ( string $class = "stdClass" , array $constructor_args = [] ) : object|null|false

过程化风格

mysqli_fetch_object ( mysqli_result $result , string $class = "stdClass" , array $constructor_args = [] ) : object|null|false

Returns the current row result set as an object where the attributes of the object represent the names of the fields found within the result set.

If two or more columns of the result have the same name, the last column will take precedence and overwrite any previous data. To access multiple columns with the same name, mysqli_fetch_row() may be used to fetch the numerically indexed array, or aliases may be used in the SQL query select list to give columns different names.

Note: This function sets the properties of the object before calling the object constructor.

Note: 此函数返回的字段名大小写敏感

Note: 此函数将 NULL 字段设置为 PHP null 值。

参数

result

仅以过程化样式:由 mysqli_query()mysqli_store_result()mysqli_use_result()mysqli_stmt_get_result() 返回的结果集标识。

class

The name of the class to instantiate, set the properties of and return. If not specified, a stdClass object is returned.

constructor_args

An optional array of parameters to pass to the constructor for class objects.

返回值

Returns an object representing the fetched row, where each property represents the name of the result set's column, or null if there are no more rows in the result set.

更新日志

版本 说明
8.0.0 constructor_args now accepts [] for constructors with 0 parameters; previously an exception was thrown.

范例

Example #1 mysqli_result::fetch_object() example

面向对象风格

<?php

mysqli_report
(MYSQLI_REPORT_ERROR MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost""my_user""my_password""world");
 
$query "SELECT Name, CountryCode FROM City ORDER BY ID DESC";

$result $mysqli->query($query);

/* fetch object array */
while ($obj $result->fetch_object()) {
    
printf("%s (%s)\n"$obj->Name$obj->CountryCode);
}

过程化风格

<?php

mysqli_report
(MYSQLI_REPORT_ERROR MYSQLI_REPORT_STRICT);
$link mysqli_connect("localhost""my_user""my_password""world");

$query "SELECT Name, CountryCode FROM City ORDER BY ID DESC";

$result mysqli_query($link$query);

/* fetch associative array */
while ($obj mysqli_fetch_object($result)) {
    
printf("%s (%s)\n"$obj->Name$obj->CountryCode);
}

以上例程的输出类似于:

Pueblo (USA)
Arvada (USA)
Cape Coral (USA)
Green Bay (USA)
Santa Clara (USA)

参见

User Contributed Notes

fedge-no at hotmail dot calm 15-Nov-2016 07:48
I checked the bug database and as long as your PHP installation is up to date, the order of setting properties and calling the constructor should now follow the order specified in the documentation. There was a little while that a patch had been introduced where it was happening the other way around but that has been fixed now.
macole at paypal dot com 30-Jun-2016 02:56
Note that if you supply a class that has a __set() magic method defined in it, that method will be called for any properties that are not defined in your class.  For example:

<?php

class SomeClass {
    private
$id;
    public
$partner_name;
    public function
__set( $name, $value ) {
        echo
"__set was called!  Name = $name\n";
       
$this->$name = $value;
    }
}

$db = new mysqli( 'localhost', 'Username', 'Password', 'DbName' );
$result = $db->query( 'SELECT id, partner_name, partner_type FROM submissions' );
$object = $result->fetch_object( 'SomeClass' );

?>

Produces the following output:

__set was called!  Name = partner_type
neo22s at gmail dot com 08-May-2016 08:04
Since 5.6.21 and PHP 7.0.6

mysqli_fetch_object() sets the properties of the object AFTER calling the object constructor. Not BEFORE as was in previous versions.

So behaviour has changed. Seems a bug but not sure if was done intentionally.

https://bugs.php.net/bug.php?id=72151
object-array at gmail dot com 17-Feb-2016 08:56
Please mind the difference between objects and arrays in PHP>=5: arrays are by value while objects are by reference.

<?
$o = mysqli_fetch_object($res);
$o1 = $o;
$o1->value = 10;

$a = mysqli_fetch_array($res);
$a1 = $a;
$a1['value'] = 10;

echo $o->value; // 10
echo $a['value']; // (original value from db)
?>

Should same behaviour be intended, the object needs to be cloned:

<?
$o1 = clone $o;
?>

More about object cloning:
http://php.net/manual/en/language.oop5.cloning.php
me at philkershaw dot me 28-Mar-2014 05:02
As a best practice, if you intend to use a defined class when using fetching_object(). Put the data obtaining code within a static method of the defined class. Otherwise, wherever you include the file (if not using an autoloader) the data connection will occur whether you want it to or not.

For example:

<?php

class User
{
    public
$name;

    public static function
getUser($id)
    {
       
$conn = new mysqli('localhost', 'username', 'password', 'database');
        if (
$result = $conn->query("SELECT * FROM users WHERE id = {$id} LIMIT 1")) {
            return
$result->fetch_object('User');
           
$result->close();
        }
    }
}
?>

Call the static method to obtain an instance of the User class with your data applied to it.

<?php
$user
= User::getUser('31');
echo
$user->name; // echo's 'Phil'
?>
Driek 26-Jun-2012 05:18
As indicated in the user comments of the mysql_fetch_object, it is important to realize that class fields get values assigned to them BEFORE the constructor is called.
For example;
<?php

class Employee
{
  private
$id;

  public function
__construct($id = 0)
  {
   
$this->id = $id;
  }
}

// some code for creating a database connection... i.e. mysqli object
....
$result = $con->query("select id, name from employees");
$anEmployee = $result->fetch_object("Employee");
?>
will result in the ID being 0 because it is overridden by the constructor. Therefore, it is useful to check if the class field is already set.
I.e.
<?php
class Employee
{
  private
$id;

  public function
__construct($id = 0)
  {
    if (!
$this->id)
    {
      
$this->id = $id
   
}
  }
}
?>
Also note that the fields which will be assigned by fetch_object are case sensitive. If your table has the field "ID", it will result in the class field $ID being set. A simple work-around is to use aliases. I.e. "SELECT *, ID as id FROM myTable"
I hope this helps some people.
Alex 27-Jan-2012 04:36
Make sure to specify the full namespace for the "string $class_name" parameter and not a partial one, as it won't find it. For example:

<?php

namespace Root(backslash)FirstLevel
{
    public static function
Test($result)
    {
        return
mysqli_fetch_object($result, 'SecondLevel\\MyClass');
    }
}

?>

... will not work but this will:

<?php

namespace Root(backslash)FirstLevel
{
    public static function
Test($result)
    {
        return
mysqli_fetch_object($result, 'Root\\FirstLevel\\SecondLevel\\MyClass');
    }
}

?>
benpptung at tacol dot biz 08-Aug-2009 08:04
I don't know why no one talk about this.
fetch_object is very powerful since you can instantiate an Object which has the methods you wanna have.

You can try like this..

<?php
class PowerfulVO extends AbstractWhatEver {

    public
$field1;
    private
$field2; // note : private is ok

   
public function method(){
      
// method in this class
   
}
}

    
$sql = "SELECT * FROM table ..."
    
$mysqli = new mysqli(........);
    
$result = $mysqli->query($sql);
    
$vo = $result->fetch_object('PowerfulVO');
?>

Note : if the field is not defined in the class, fetch_object will add this field for you as public.

The method is very powerful, especially if you want to use a VO design pattern or class mapping feature with Flex Remoting Object( Of course, you need to have ZendAMF or AMFPHP ..framework)

Hope this help and open new possibilities for you
peterbelm at g[oogle]mail dot com 18-Aug-2008 07:10
If your SQL code selects columns with empty names like so:

SELECT id as ``...

You will get a fatal error "Cannot access empty property", this took me a while to track down!

Obviously your SQL really shouldn't do that, and should be fixed but I'm going to submit a feature request to ask for a better error message for that.
PHP8中文手册 站长在线 整理 版权归PHP文档组所有